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= 1,38064852e-22 m ^ 2 kg s ^ -2 k ^ -1

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Answer to Calculate the entropy S for the following system k b = 1.38 x 10 -23 m 2 kg s -2 K -1 considering only positional microstates and neglecting

b). Laplace transform of EOM. c). X1 (s) and X2 (s) expression without solving. s = 1Q + ( ) 2 2 2 1 2 2 V m h h - - + The mass flow rate is given by m = 1 1 AV v The specific velocity can be determine from ideal gas law v 1 = ( ) 1 1 R / M T p = 5 2 8314 N m (290 K) 28.97 kg K 10 N/m × × = 0.8324 kg/m3 The mass flow rate is then m = 1 1 1 AV v = (2)( ) 3 0.1 m 6 m/s 0.8324 kg/m = 0.7209 kg/s The change in air enthalpy Problem 15.73! An object of mass m1 = 9 kg is in equilibrium when connected to a light spring of constant k = 100 N/m that is fastened to a wall. A second object m2 = 7 kg is slowly pushed up against m1 Dec 21, 2017 · < v^2 > ~~8.8xx10^4"m"//"s" Both kinetic energy and the ideal gas law provide expressions for pressure.

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8 4 = 2.37 10 -7 kg/s To find = 2 ) 20 . 0 ( 4 A = 0.0314 m 2 G - Universal gas constant = 8314 K mole kg J p - Total pressure = 1 atm = 1.013 bar = 1.013 x 10 5 N/m 2 p wl = Partial pressure at the 2018-04-26 1 Pascal = 1 N/m2 or 1 Kg / m.s2 . Kilogram force per square meter to Pascals table. Start Increments Accuracy Format Print table < Smaller Values Larger Values > Kilogram force per square meter Pascals; 0 kg/m2: 0.00 Pa: 1 kg/m2: 9.81 Pa: 2 kg/m2: 19.61 Pa: 3 kg/m2: 29.42 Pa: 4 kg/m2: 39.23 Pa: 5 kg/m2: 49.03 Pa: 6 kg/m2: 58.84 Pa: 7 kg/m2: 68.65 Pa: 8 kg/m2: 78.45 Pa: 9 kg/m2: 88.26 Putting the values in the above equations, we get x 2 = 0. 0 2 m and x 1 = 0.

4217 J/kg⋅K, μ l =279 × 10-6 N⋅s/m2, Pr l = 1.76, h fg = 2257 kJ/kg, σ = 58.9 × 10-3 N/m; Table A-6, Saturated water, vapor (1 atm): ρ

= 1,38064852e-22 m ^ 2 kg s ^ -2 k ^ -1

E k = 14.125 kg m 2 /sec 2 = 14.125 Joules [2] If the kinetic energy of a car is 320,000 Joules (3.2 x 10 5 J), and it's velocity is 25 m/s, what is the vehicle's mass? Answer: The kinetic energy for the car in motion is E k = 320,000 J = 32,000 kg m 2 /s 2 .

= 1,38064852e-22 m ^ 2 kg s ^ -2 k ^ -1

1000 kg m^2/s^2 to kilojoules = 1 kilojoules ›› Want other units? You can do the reverse unit conversion from kilojoules to kg m^2/s^2, or enter any two units below: Enter two units to convert. From: To: ›› Definition: Kilojoules. The SI prefix "kilo" represents a factor of 10 3, or in exponential notation, 1E3. So 1 kilojoules = 10 3 joules. ›› Metric conversions and more

= 1,38064852e-22 m ^ 2 kg s ^ -2 k ^ -1

Then find x(t) as a func tion of time t.

0 ( 4 A = 0.0314 m 2 G - Universal gas constant = 8314 K mole kg J p - Total pressure = 1 atm = 1.013 bar = 1.013 Dec 18, 2010 · The joule is a unit of energy equal to the work done when a force of one newton (1 kg*m/s^2) acts through a distance of one meter. 1 N*1 m = 1 Kg*m/s^2 * 1 m = 1 Kg*m^2/s^2 = 1 J. If you are talking about eating something, you might be better off converting joules to calories -- a more recognizable engineering unit of heat. Jan 16, 2013 · And for Pa, your analysis is right on point. N/m^2 ~ kg.m/s^2//m^2 ~ kg/(m.s^2) are all equivalent, as you surmised. This is why I argue against arcane name calling for units.

(b) Determine the speed of the wave. (c) If the string has a mass/unit length of m = 0.012 kg/m, determine the tension in the string. v = 486.8 m/s Here is the above set-up done with units: v = [(3) (8.31447 kg m 2 s-2 K-1 mol-1) (304.0 K) / 0.0319988 kg/mol. Remember that kg m 2 s-2 is called a Joule and that the unit on R is usually written J/K mol. The more extended unit of J must be used in this particular type of problem. May 06, 2017 · The De Broglie equation states that the #"KE" = (1/2)"mv"^2# #"Where KE is kinetic energy"# #"Where m is mass and is a constant for each particle"# So, pw2 -0.Diameter d = 20 cm = 0.20 m Length (x 2 -x 1 ) = 8cm = 0.08 m Temperature ,T= 25 o C+273 = 298 K Diffusion rate (or) Mass rate of water vapour = 8.54 10 -4 kg/h = s kg 3600 10 54 .

K −1, where the kilogram, metre and second are defined in terms of . h, c. and ∆ν . Cs. amount of substance . The .

= 10 ms-1. If, after 10 s, its energy is mvą, the value of k will be (1) 10-3 kg m (2) 10-3 kg s-1 (3) 104 kg m-1 (4) 10-1 kg m-'s-1 Mass flux density unit conversion between kilogram/second/square meter and pound/second/square foot, pound/second/square foot to kilogram/second/square meter conversion in batch, kg/(s.m2) lb/(s.ft2) conversion chart 1 W i d e - Ru l e d C o m p o s i t i o n N o te b o o k 2 fo l d e r s - o n e re d / o n e b l u e 1 Pai r H e ad p h o n e s to s t ay at s c h o o l 1 P kg P i n k E ras e r s 1 Pe n c i l B ox ( 8 i n . X 5 i n . X 2 i n .) Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals.

The increase in speed also increases the kinetic energy. The v = 486.8 m/s Here is the above set-up done with units: v = [(3) (8.31447 kg m 2 s-2 K-1 mol-1) (304.0 K) / 0.0319988 kg/mol. Remember that kg m 2 s-2 is called a Joule and that the unit on R is usually written J/K mol. The more extended unit of J must be used in this particular type of problem. The joule is a unit of energy equal to the work done when a force of one newton (1 kg*m/s^2) acts through a distance of one meter. 1 N*1 m = 1 Kg*m/s^2 * 1 m = 1 Kg*m^2/s^2 = 1 J. If you are talking about eating something, you might be better off converting joules to calories -- a more recognizable engineering unit of heat. Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals.

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May 06, 2017 · The De Broglie equation states that the #"KE" = (1/2)"mv"^2# #"Where KE is kinetic energy"# #"Where m is mass and is a constant for each particle"#

Answer: The kinetic energy for the car in motion is E k = 320,000 J = 32,000 kg m 2 /s 2 . = 0 − 2 g(0 − h ) v = 2 gh = 2 (9.8 m /s2)(10 m ) =14 m /s Initial: k = 1 2 mv 2 = 0 Final : k = 1 2 mv 2 = 1 2 (3 kg )(14 m /s)2 = 294 J So as the ball falls, its kinetic energy increases. It is the gravitational force that accelerates the ball, causing the speed to increase. The increase in speed also increases the kinetic energy.